[프로그래머스] [MySQL] [Level 3] [GROUP BY] 즐겨찾기가 가장 많은 식당 정보 출력하기

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SELECT FOOD_TYPE, REST_ID, REST_NAME, FAVORITES
FROM REST_INFO
WHERE (FOOD_TYPE, FAVORITES) IN 
(SELECT FOOD_TYPE, MAX(FAVORITES) 
 FROM REST_INFO 
 GROUP BY FOOD_TYPE)
ORDER BY FOOD_TYPE DESC;