PROGRAMMERS/SQL
[프로그래머스] [MySQL] [Level 2] [SUM, MAX, MIN] 가격이 제일 비싼 식품의 정보 출력하기
c0mmedes
2022. 10. 13. 00:59
SELECT PRODUCT_ID, PRODUCT_NAME, PRODUCT_CD, CATEGORY, PRICE
FROM FOOD_PRODUCT
WHERE PRICE = (SELECT MAX(PRICE) FROM FOOD_PRODUCT)
SELECT PRODUCT_ID, PRODUCT_NAME, PRODUCT_CD, CATEGORY, PRICE
FROM FOOD_PRODUCT
WHERE PRICE IN (SELECT MAX(PRICE) FROM FOOD_PRODUCT)
SELECT PRODUCT_ID, PRODUCT_NAME, PRODUCT_CD, CATEGORY, PRICE
FROM FOOD_PRODUCT
ORDER BY PRICE DESC
LIMIT 1