[프로그래머스] [MySQL] [Level 3] [JOIN] 오랜 기간 보호한 동물(1)

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-- 코드를 입력하세요
SELECT ANIMAL_INS.NAME, ANIMAL_INS.DATETIME
FROM ANIMAL_INS
LEFT JOIN ANIMAL_OUTS
ON ANIMAL_INS.ANIMAL_ID = ANIMAL_OUTS.ANIMAL_ID
WHERE ANIMAL_OUTS.ANIMAL_ID is NULL
ORDER BY DATETIME
LIMIT 3